What is the prevalence proportion of meningitis in the region thus far this year given 39 cases among 84,000 children aged 15 years and younger?

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Multiple Choice

What is the prevalence proportion of meningitis in the region thus far this year given 39 cases among 84,000 children aged 15 years and younger?

Explanation:
The question tests how to calculate a prevalence proportion. You take the number of existing cases and divide by the population at risk, then express that ratio per a standard population size, here per 100,000. So, 39 meningitis cases among 84,000 children aged 15 years and younger gives: 39 ÷ 84,000 = 0.000464, which is 0.0464%. Multiplying by 100,000 to express per 100,000 people: 0.000464 × 100,000 ≈ 46.4. Rounded, the prevalence proportion is about 46 per 100,000. The other options would require a different number of cases or a different population size (for example, 42 cases would be 50 per 100,000, and about 3–4 cases would be around 4–5 per 100,000), so they don’t match the given data.

The question tests how to calculate a prevalence proportion. You take the number of existing cases and divide by the population at risk, then express that ratio per a standard population size, here per 100,000.

So, 39 meningitis cases among 84,000 children aged 15 years and younger gives:

39 ÷ 84,000 = 0.000464, which is 0.0464%.

Multiplying by 100,000 to express per 100,000 people: 0.000464 × 100,000 ≈ 46.4.

Rounded, the prevalence proportion is about 46 per 100,000. The other options would require a different number of cases or a different population size (for example, 42 cases would be 50 per 100,000, and about 3–4 cases would be around 4–5 per 100,000), so they don’t match the given data.

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